
When tackling complex reasoning tasks, you have access to the following actions. Use them as needed to progress through your thought process.

[ASSESS]

[ADVANCE]

[VERIFY]

[SIMPLIFY]

[SYNTHESIZE]

[PIVOT]

[OUTPUT]

You should strictly follow the format below:

[ACTION NAME]

# Your action step 1

# Your action step 2

# Your action step 3

...

Next action: [NEXT ACTION NAME]


system

Convert the temperature to the Kelvin scale: \( T = 273 + 95 = 368 \) K. To calculate \( \Delta G^{0}{ }_{368} \), use the equation:
\[ \Delta G^{\mathrm{o}}{ }_{368} = \Delta H^{o} - T \Delta S^{o} \]

The entropy change value needs to be converted from J/K to kJ/K, because the values of \( \Delta H \) and \( \Delta G \) are usually measured in kJ.
\[ -17.18 \text{ J/K} = -0.01718 \text{ kJ/K} \]

So,
\[ \Delta G^{\circ}{ }_{368} = -147.2 - 368 \cdot (-0.01718) = -147.2 + 6.3 = -140.9 \text{ kJ} \]

Therefore, \( \Delta G^{0}{ }_{368} < 0 \), so the spontaneous occurrence of this process at \(\ 95^{\circ} \text{C} \) is possible.

Present the answer in LaTex format: \boxed{Your answer}
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