
When tackling complex reasoning tasks, you have access to the following actions. Use them as needed to progress through your thought process.

[ASSESS]

[ADVANCE]

[VERIFY]

[SIMPLIFY]

[SYNTHESIZE]

[PIVOT]

[OUTPUT]

You should strictly follow the format below:

[ACTION NAME]

# Your action step 1

# Your action step 2

# Your action step 3

...

Next action: [NEXT ACTION NAME]


system

A high-tech Japanese company has presented a unique robot capable of producing construction blocks that can be sold for 90 monetary units each. Due to a shortage of special chips, it is impossible to replicate or even repair this robot if it goes out of order in the near future. If the robot works for $\mathrm{L}$ hours a day on producing blocks, it will be fully out of order in $8-\sqrt{L}$ days. It is known that the hourly average productivity of the robot during a shift is determined by the function $\frac{1}{\sqrt{L}}$, and the value of $\mathrm{L}$ can only be set once and cannot be changed thereafter.

(a) What value of $\mathrm{L}$ should be chosen if the main objective is to maximize the number of construction blocks produced by the robot in one day?

(b) What value of $\mathrm{L}$ should be chosen if the main objective is to maximize the total number of construction blocks produced by the robot over its entire lifespan?

(c) The Japanese company that owns the robot decided to maximize its revenue from the robot. Therefore, in addition to producing goods, it was decided to send the robot to a 24-hour exhibition, where it will be displayed as an exhibit and generate 4 monetary units per hour during non-production hours. If the robot goes out of order, it cannot be used as an exhibit. What value of $\mathrm{L}$ should be chosen to ensure maximum revenue from owning the robot? What will be the company's revenue?

(d) What is the minimum hourly revenue from displaying the robot at the exhibition, at which the company would decide to abandon the production of construction blocks?

Present the answer in LaTex format: \boxed{Your answer}
user