
When tackling complex reasoning tasks, you have access to the following actions. Use them as needed to progress through your thought process.

[ASSESS]

[ADVANCE]

[VERIFY]

[SIMPLIFY]

[SYNTHESIZE]

[PIVOT]

[OUTPUT]

You should strictly follow the format below:

[ACTION NAME]

# Your action step 1

# Your action step 2

# Your action step 3

...

Next action: [NEXT ACTION NAME]


system
Given the following propositions:

 \\(①\\) The winning rate of a lottery ticket is \\( \dfrac{1}{10,000} \\), buying \\(10,000\\) tickets guarantees a win.

 \\(②\\) A student tosses a fair coin \\(100\\) times, and in the first \\(99\\) tosses, there are \\(90\\) tails and \\(9\\) heads. Thus, the probability of getting heads on the \\(100\\)th toss is higher.

 \\(③\\) For any two events _\\(A\\)_ and _\\(B\\)_, _\\(P\\)_\\((\\)_\\(A\\)_\\(+\\)_\\(B\\)_\\()=\\)_\\(P\\)_\\((\\)_\\(A\\)_\\()+\\)_\\(P\\)_\\((\\)_\\(B\\)_\\().\\)

 \\(④\\) According to the definition of probability, if a random event _\\(A\\)_ occurs _\\(m\\)_ times in _\\(n\\)_ trials, then when the number of trials is large, the frequency of event _\\(A\\)_ occurring, \\( \dfrac{m}{n} \\), can be used as an approximate value of the probability of event \\(A\\), i.e., _\\(P\\)_\\((\\)_\\(A\\)_\\()≈ \dfrac{m}{n}\\).\\)

 \\(⑤\\) Tossing a fair coin \\(100,000\\) times and \\(1,000,000\\) times, in terms of the frequency of getting heads, tossing it \\(1,000,000\\) times will definitely be closer to \\( \dfrac{1}{2} \\) than tossing it \\(100,000\\) times.

 Among these, the correct proposition numbers are                 \\(.(\\)List all the correct proposition numbers\\()\\)

Present the answer in LaTex format: \boxed{Your answer}
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