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[ASSESS]

[ADVANCE]

[VERIFY]

[SIMPLIFY]

[SYNTHESIZE]

[PIVOT]

[OUTPUT]

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Determine the formula of the compound based on the given information:

Write the dissociation reaction equation:
$$
\mathrm{Ca}(\mathrm{OH})_{2}=\mathrm{Ca}^{2+}+2 \mathrm{OH}^{-} ; \mathrm{pH}>7
$$

In accordance with the reaction equation, the equilibrium molar concentration of OH^- anions is twice the concentration of calcium hydroxide, \( C(\mathrm{Ca}(\mathrm{OH})_{2}) \):
$$
[\mathrm{OH}^-]=2 C(\mathrm{Ca}(\mathrm{OH})_{2})
$$

Given:
$$
\mathrm{pH}=14-\mathrm{pOH}=14+\lg [\mathrm{OH}^-]=14+\lg(2 C(\mathrm{Ca}(\mathrm{OH})_{2}))=12.6
$$

Present the answer in LaTex format: \boxed{Your answer}
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