
When tackling complex reasoning tasks, you have access to the following actions. Use them as needed to progress through your thought process.

[ASSESS]

[ADVANCE]

[VERIFY]

[SIMPLIFY]

[SYNTHESIZE]

[PIVOT]

[OUTPUT]

You should strictly follow the format below:

[ACTION NAME]

# Your action step 1

# Your action step 2

# Your action step 3

...

Next action: [NEXT ACTION NAME]


system
Let's denote the desired number as $\overline{a b c d} = 1000a + 100b + 10c + d$. Then, another number will be $\overline{d c b a} = 1000d + 100c + 10b + a$. The sum of these numbers will be $1001a + 110b + 110c + 1001d$. Since dividing this sum by 143 yielded 136, we have the equation: $1001(a + d) + 110(b + c) = 19448$. Since $(b + c)$ does not exceed 18, it means $110(b + c)$ does not exceed 1980. From the equation, we find that equality is possible only when $a = d = 9$. Then we have: $110(b + c) = 19448 - 18018$, which is equivalent to the equation: $b + c = 13$. By iterating through all possible values for $b$ and $c$, we obtain 6 possible four-digit numbers that satisfy the condition: 9949, 9859, 9769, 9679, 9589, 9499.

Present the answer in LaTex format: \boxed{Your answer}
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