Let's introduce some definitions that will be needed later.

Let $prime(x)$ be the set of prime divisors of $x$. For example, $prime(140) = \{ 2, 5, 7 \}$, $prime(169) = \{ 13 \}$.

Let $g(x, p)$ be the maximum possible integer $p^k$ where $k$ is an integer such that $x$ is divisible by $p^k$. For example:  $g(45, 3) = 9$ ($45$ is divisible by $3^2=9$ but not divisible by $3^3=27$),  $g(63, 7) = 7$ ($63$ is divisible by $7^1=7$ but not divisible by $7^2=49$). 

Let $f(x, y)$ be the product of $g(y, p)$ for all $p$ in $prime(x)$. For example:  $f(30, 70) = g(70, 2) \cdot g(70, 3) \cdot g(70, 5) = 2^1 \cdot 3^0 \cdot 5^1 = 10$,  $f(525, 63) = g(63, 3) \cdot g(63, 5) \cdot g(63, 7) = 3^2 \cdot 5^0 \cdot 7^1 = 63$. 

You have integers $x$ and $n$. Calculate $f(x, 1) \cdot f(x, 2) \cdot \ldots \cdot f(x, n) \bmod{(10^{9} + 7)}$.


-----Input-----

The only line contains integers $x$ and $n$ ($2 \le x \le 10^{9}$, $1 \le n \le 10^{18}$) — the numbers used in formula.


-----Output-----

Print the answer.


-----Examples-----
Input
10 2

Output
2

Input
20190929 1605

Output
363165664

Input
947 987654321987654321

Output
593574252



-----Note-----

In the first example, $f(10, 1) = g(1, 2) \cdot g(1, 5) = 1$, $f(10, 2) = g(2, 2) \cdot g(2, 5) = 2$.

In the second example, actual value of formula is approximately $1.597 \cdot 10^{171}$. Make sure you print the answer modulo $(10^{9} + 7)$.

In the third example, be careful about overflow issue.